(3xy/z)^-2

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Solution for (3xy/z)^-2 equation: 


8*ln(cos(t))

5-12 = z/(-8)

((x^2)/4)/(((x^2*y)/12)*y^2) = 0

6/7 = 48/x

15*x^2-((12*x)/3) = 0

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